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Performance of Australia at the 2003 Fed Cup
Australia at the 2003 Fed Cup played the matches in the 1st Round against Spain. In the first rubber of this round, A.Molik of Australia defeated V.Ruano Pascal of Spain by 6-3 and 6-4. In the second match, M.Serna of Spain defeated N.Pratt of Australia by 6-3 and 6-2.
In the third match, C.Martinez of Spain defeated N.Pratt of Australia in sets with the score of 6-1 and 6-2. In the fourth match, M.Serna of Spain defeated A.Molik of Australia by 6-4 and 6-1.
In the doubles match, R.Stubbs and A.Molik of Australia defeated V.Ruano Pascual and A.Medina of Spain by 4-6, 6-2 and 6-3. Thus, Spain defeated Australia by a score of 3-2 in the matches of this round.
Australia played matches of World Group, Play-offs against Colombia on 20th July. In the first rubber, F.Zuluaga of Colombia defeated S.Stosur of Australia in sets of 4-6, 6-1 and 6-4. In the second rubber, A.Molik of Australia defeated C.Castano of Colombia by 7-6(6), 4-6 and 6-2.
In the third rubber, F.Zuluaga of Colombia defeated A.Molik of Australia by 6-2, 6-7(4) and 10-8. In the fourth rubber, N.Pratt of Australia defeated C.Castano of Colombia in sets of 6-3 and 7-6(3).
In the fifth rubber, R.Stubbs and A.Molik of Australia defeated F.Zuluaga and C.Castano of Colombia in straight sets of 7-6(5) and 6-2. Thus, Australia defeated Colombia by a score of 3-2 in the Playoffs.
Summary of performance of Australia at the 2003 Fed Cup
Matches played: 5 in 1st Round and 5 in World Group, Playoffs
Matches won: 2 in 1st Round and 3 in World Group, Playoffs
Matches lost: 3 in 1st Round and 2 in World Group, Playoffs
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